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6n^2+18n-108=0
a = 6; b = 18; c = -108;
Δ = b2-4ac
Δ = 182-4·6·(-108)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-54}{2*6}=\frac{-72}{12} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+54}{2*6}=\frac{36}{12} =3 $
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